graph 4x 5y=20 | BTCC Learning Hub

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To solve the linear equation 4x + 5y = 20 for y, rearrange it to y = (20 - 4x) / 5. The x-intercept is found by setting y to 0, yielding x = 5. The y-intercept is found by setting x to 0, yielding y = 4. A third check point can be found by substituting a value for x or y and solving for the other variable. To draw the graph, plot these points and connect them with a straight line. The system of linear equations 4x - 5y - 20 = 0 and 3x + 5y - 15 = 0 can be solved graphically by finding the intersection of their lines on a coordinate plane.

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